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How much ORACLE 1Z0-071 Certification Exam cost:
The organization charges nominal assessment fees. A single attempt fee is charged at the time of the attempt. The average number of attempts a candidate can take before being required to make a payment is unlimited.
Ongoing renewal charges are paid by credit card at the beginning of every month until the certification exam has been passed, regardless if it's been taken or not. This charge automatically stops once you have passed your certification exam, and you can give a response at any point in time to continue taking the exam again free of charge. The cost for the ORACLE 1Z0-071 Certification Exam varies according to region. You can pay a premium fee in the bank or through the online channel. Following are some figures about the cost of exam 1Z0-071.
- In Canada cost for the 1Z0-071 exam is 297 USD
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Oracle Database SQL Sample Questions (Q152-Q157):
NEW QUESTION # 152
Examine the structure of the PROGRAMS table:
Which two SQL statements would execute successfully? (Choose two.)
- A. SELECT TO_DATE(NVL(SYSDATE-END_DATE,SYSDATE))FROM programs;
- B. SELECT NVL(TO_CHAR(MONTHS_BETWEEN(start-date,end_date)),'Ongoing')FROM programs;
- C. SELECT NVL(MONTHS_BETWEEN(start_date,end_date),'Ongoing')FROM programs;
- D. SELECT NVL(ADD_MONTHS(END_DATE,1)SYSDATE)FROM programs;
Answer: A,B
NEW QUESTION # 153
Which three statements are true? (Choose three.)
- A. Both USER_OBJECTS and CAT views provide the same information about all objects that are owned by the user.
- B. The data dictionary is created and maintained by the database administrator.
- C. Data dictionary views consist of joins of dictionary base tables and user-defined tables.
- D. The usernames of all users including database administrators are stored in the data dictionary.
- E. The USER_CONS_COLUMNS view should be queried to find the names of columns to which constraints apply.
- F. Views with the same name but different prefixes, such as DBA, ALL and USER, reference the same base tables from the data dictionary.
Answer: D,E,F
Explanation:
References:
https://docs.oracle.com/cd/B10501_01/server.920/a96524/c05dicti.htm
NEW QUESTION # 154
Examine the description of the MEMBERS table;
SELECT city,last_name LNAME FROM members ...
You want to display all cities that contain the string AN. The cities must be returned in ascending order, with the last names further sorted in descending order.
Which two clauses must you add to the query?
- A. ORDER BY last_name DESC,city ASC
- B. ORDER BY 1,2.
- C. CORADER BY 1, LNAME DESC
- D. WHERE city LIKE '%AN%;
- E. WHERE city IN ('%AN%')
- F. WHERE city='%AN%;
Answer: C,D
Explanation:
To achieve the desired output for the query from the MEMBERS table:
* C. ORDER BY 1, LNAME DESC: This clause correctly sorts the results first by the first column (city) in ascending order by default, and then by the alias LNAME (last_name) in descending order.
* E. WHERE city LIKE '%AN%': This clause correctly filters the rows to include only those cities containing the string 'AN' anywhere in the city name, using the LIKE operator which is suitable for pattern matching.
Incorrect options:
* A: This would order both columns in ascending order, which does not meet the requirement for last_name to be in descending order.
* B: This misplaces the order priorities and uses explicit column names that contradict the sorting requirement specified.
* D: Incorrect syntax for a LIKE clause; equality operator cannot be used with wildcards.
* F: The IN operator is incorrectly used here with a pattern, which is not valid syntax.
NEW QUESTION # 155
Examine the structure of the PROMOTIONS table: (Choose the best answer.)
Management requires a report of unique promotion costs in each promotion category.
Which query would satisfy this requirement?
- A. SELECT promo_category, DISTINCT promo_cost FROM promotions
- B. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1
- C. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;
- D. SELECT DISTINCT promo_cost, promo_category FROM promotions
Answer: B
NEW QUESTION # 156
Examine the description of the EMPLOYEES table:
NLS_DATE FORMAT is DD-MON-RR.
Which two queries will execute successfully?
- A. SELECT dept_ id, AVG(MAX(salary)) FROM employees GROUP BY dept_id, salary;
- B. SELECT dept_ iD, sum(salary) FROM employees WHERE hire_date > '01-JAN-9' GROUP BY dept_id;
- C. SELECT dept_ id, AVG (MAX(salary)) FROM employees GROUP By dept_id HAVING hire_date> ' O1-JAN-19';
- D. SELECT dept id, MAX (SUM(salary)) FROM employees GROUP BY dept_id;
- E. SELECT AVG(MAX(salary)) FROM employees GROUP BY salary;
Answer: B
Explanation:
In Oracle SQL, aggregation functions such as AVG and MAX cannot be nested directly inside each other and must be used in conjunction with GROUP BY on the column(s) that are not included in the aggregate function.
Also, the HAVING clause filters groups after aggregation is applied.
A). This query will not execute successfully because it improperly nests MAX inside AVG. Oracle SQL does not allow this type of nested aggregation without a subquery.
B). This query will not execute successfully for the same reason as A, it improperly nests MAX inside AVG.
C). Similar to A and B, this query improperly nests SUM inside MAX, which is not allowed without a subquery.
D). This query will execute successfully. It filters rows based on the HIRE_DATE using a correct date format (assuming '9' refers to '09' or '1999' due to the NLS_DATE_FORMAT being 'DD-MON-RR'), then groups the remaining rows by DEPT_ID and calculates the sum of SALARY for each department.
E). This query will not execute successfully because it improperly nests MAX inside AVG without a subquery, and it incorrectly attempts to GROUP BY SALARY, which is already being aggregated.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Aggregate Functions"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "GROUP BY Clause"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "HAVING Clause"
NEW QUESTION # 157
......
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